f = a?x + bt 2 , where [f] = [M L T ?2 ], [x] = [L] and [t] = [T]. LHS is force. So both the terms on the RHS have the dimensions of force. [f] = [a?x] = [bt 2 ] [f] = [a?x] [M L T ?2] = [a L ½] ? [a] = [M L ½ T ?2] [f] = [bt 2 ] [M L T ?2] = [ b T 2 ], 1/15/2019 · Correct option ( b ) [L-1/2 T 2] Explanation : Given, F = A ? x + Bt 2 . Here, F = force, x = distance and t = time, answer. answered. 6. Find the dimensions of a / b in the equation : F=a ?x + bt2 , where F is force, x is distance and t is time. 2. See answers. report flag outlined. bell outlined. Log in to add comment.
find the dimensions of a/b in the equation f=a route x +bt square where f is the force x is the distance and t is the time, According to homogeneity principleDimensional Formula of F = Dimensional Formula of at = Dimensional Formula of bt2We know that Dimensional Formula of F = [M LT ?2]So, Dimensional Formula of at = [M LT ?2]? Dimensional Formula of a = [M LT ?3]Also,Dimensional Formula of bt2 = [M LT ?2]? Dimensional Formula of b = [M LT ?4] Answer By Toppr.
6. Find the dimensions of a / b in the equation: F=a ?x +bt2 , where F …
What are the dimensions of A/B in the relation F = A ? x + Bt^2 …
Assume Equation Bt Describes Motion Particular Object, 6. Find the dimensions of a / b in the equation: F=a ?x +bt2 , where F …
F=a root x +bt 2 . So, dimension of F = a root x. m / (s 2) = a root (metre) So . a = m / (s 2) divided by root(metre) Squaring both sides and solving we get–a 2 = m / s 4 — equation 1st. Now. dimension of F = dimension of bt 2 . Solve it and you will get . b 2 = m 2 / s 8 — equation 2. Now divide equation 2 by q. you will get –a / b = s 4 / m. So converting in dimensions, (a) Assume the equation x = At3 + Bt describes the motion of a particular object, with x having the dimension of length and t having the dimension of time. Determine the dimensions of the constants A and B . (Use the following as necessary: L and T, where L is the unit of length and T is the unit of time.), Question: Assume The Equation X = At^t + Bt^2 Describes The Motion Of A Particular Object, With X Having The Dimension Of Length And T Having The Dimension Of Time. (a) Determine The Dimensions Of The Constants A And B . ( b ) Find The Derivative Of X With Respect To T. (c) Determine The Dimensions Of The Derivative Dx/dt.
Click here??to get an answer to your question ? Find the dimensions of a & b if F = at + bt^2, The dimensions of a/b in the equation P=a- t 2 /bx where P is pressure, x is distance and t is time are.
